MCQ
$[Mn(CO)_4 NO]$ is diamagnetic because
- A$Mn$ metal is diamagnetic in free state
- B$Mn$ is in $+1$ oxidation state in this complex
- C$NO$ is present as positive ligand
- ✓All of the above
$[\overset{-1}{\mathop{Mn}}\,{{(CO)}_{4}}(N{{O}^{+}})]:$ No unpaired $e^-$ either on ligands or on $\overset{-1}{\mathop{Mn}}$ hence it is diamagnetic
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
(Use $R =8.31\, J\, K ^{-1}\, mol ^{-1} ; \log 2=0.3010$. In $10=$ $2.3, \log 3=0.477$ )