MCQ
$[Mn(CO)_4 NO]$ is diamagnetic because
  • A
    $Mn$ metal is diamagnetic in free state
  • B
    $Mn$ is in $+1$ oxidation state in this complex
  • C
    $NO$ is present as positive ligand
  • All of the above

Answer

Correct option: D.
All of the above
d
$[\overset{+1}{\mathop{Mn}}\,{{(CO)}_{4}}(N{{O}^{-}})]:$ Paramagnetic due to presence of unpaired $e^-s$ in $NO^-$

$[\overset{-1}{\mathop{Mn}}\,{{(CO)}_{4}}(N{{O}^{+}})]:$ No unpaired $e^-$ either  on ligands or on $\overset{-1}{\mathop{Mn}}$ hence it is diamagnetic

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