Mohit makes 8 full rounds of a rectangular field with length = 120 m and breadth = 75 m. John makes 10 full rounds of a square field with each side 100 in. Find who covers larger distance and by how much?

Mohit Length of the rectangular field = 120 Breadth of the rectangular field = 75 m ∴ Distance covered in one round (perim-eter) = 2(1 + b) = 2(120 + 75) = 390 m Hence, distance covered in 8 rounds = 390 x 8 m = 3120 m John Side of the field = 100 m ∴Distance covered in one round = 4 x a = 4 x 100 = 400 m Hence, Distance covered in 10 rounds = 400 x 10 m = 400 m John a covers greater distance then Mohit by = (4000-3120) m = 880 m

Mohit makes 8 full rounds of a rectangular field with length = 12…

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