MCQ
Molarity of $0.2\,N\,\,{H_2}S{O_4}$ is
- A$0.2$
- B$0.4$
- C$0.6$
- ✓$0.1$
i.e., $0.2=$ molarity $\times $ $ 2$
Molarity $ = 0.2/2 = 0.1$
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Reason : Zinc forms complex with $CuSO_4$

Which forms di-iodide on reaction with $HI $ (excess) ?