- A$36.5$
- B$18.25$
- ✓$32.05$
- D$4.65$
$1\,cc$ contains $1.17\,gm$
$\therefore 1000\,cc$ contains $1170\,gm \,\,\frac{{1170\,gm}}{{{\rm{Mol}}{\rm{.}}\,{\rm{wt}}{\rm{.}}}} = \frac{{1170}}{{36.5}} = 32.05\,mole/litre \, (Mol. wt. of HCl=36.5)$
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