Question
Multiply:
$\left(2 x y+3 y^2\right)\left(3 y^2-2\right)$

Answer

To multiply, we will use distributive law as follows:
$\left(2 x y+3 y^2\right)\left(3 y^2-2\right)$
$=2 x y\left(3 y^2-2\right)+3 y^2\left(3 y^2-2\right)$
$=6 x y^3-4 x y+9 y^4-6 y^2$
$=9 y^4+6 x y^3-6 y^2-4 x y$
Thus, the answer is $9 y^4+6 x y^3-6 y^2-4 x y$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free