Question
Multiply $(3 a+b+c)$ with $(3 a-b)$.

Answer

We have, $ (3 a+b+c) \times(3 a-b) $
$ = 3 a \times(3 a-b)+b \times(3 a-b)+c \times(3 a-b) $
$ = 9 a^2-3 a b+3 a b-b^2+3 a c-b c $
$ = 9 a^2-b^2+3 a c-b c$

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