Question
Multiply:
$\left(3 x^2+y^2\right) \text { by }\left(2 x^2+3 y^2\right)$

Answer

To multiply, we will use distributive law as follows:
$\left(3 x^2+y^2\right) \text { by }\left(2 x^2+3 y^2\right)$
$=3 x^2\left(2 x^2+3 y^2\right)+y^2\left(2 x^2+3 y^2\right)$
$=6 x^4+9 x^2 y^2+2 x^2 y^2+3 y^4$
$=6 x^4+11 x^2 y^2+3 y^4$
Thus, the answer is $6 x^4+11 x^2 y^2+3 y^4$.

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