Question
Multiply: $ (a-1) b y\left(0.1 a^2+3\right) $
✓
Answer
To multiply, we will use distributive law as follows:
$ (a-1) b y\left(0.1 a^2+3\right) $
$ =0.1 a^2(a-1)+3(a-1) $
$ =0.1 a^3-0.1 a^2+3 a-3 $
Thus, the answer is $0.1 a^3-0.1 a^2+3 a-3 $.
$ (a-1) b y\left(0.1 a^2+3\right) $
$ =0.1 a^2(a-1)+3(a-1) $
$ =0.1 a^3-0.1 a^2+3 a-3 $
Thus, the answer is $0.1 a^3-0.1 a^2+3 a-3 $.
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