Question
Multiply the binomials $(2.51 - 0.5m)$ and $(2.51 + 0.5m)$.
✓
Answer
Product of $(2.51 – 0.5m)$ and $(2.51 + 0.5m)$
$= (2.51 – 0.5m) (2.51 + 0.5m)$
$= (2.51)^2- (0.5m)^2$ [Using identity: $(a + b) (a - b) = a^2- b^2]$
$= 6.3001 - 0.25m^2$
$= (2.51 – 0.5m) (2.51 + 0.5m)$
$= (2.51)^2- (0.5m)^2$ [Using identity: $(a + b) (a - b) = a^2- b^2]$
$= 6.3001 - 0.25m^2$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The mass of equal volumes of gold and water are in the ratio 37: 2. If 1 litre of water is 1 kg in mass, what is the mass of 1 litre of gold?
Add the following rational number: $\frac{5}{-9}$ and $\frac{7}{3}$
→Write the following numbers in usual form:
$1.679 × 10^9$
→$1.679 × 10^9$
In parallelogram $ABCD$, find $\angle\text{B}.\ \angle\text{C}\ \text{and}\angle\text{D}.$
→Factorise: $2 x^2+x-45$
→Find the values of the following. $\Big(\frac{1}{2}\Big)^{-2}+\Big(\frac{1}{3}\Big)^{-2}+\Big(\frac{1}{4}\Big)^{-2}$
→How many sides does a regular polygon have, if an exterior angle is $24^{\circ}$ ?
→A train travels $\frac{1445}{2}\text{km}$ in $\frac{17}{2}\text{h}.$ Fine the speed of the train in $km/h$.
→Find the square root of number by using the method of prime factorisation:
$15876$
→$15876$
Factorise the following, using the identity $a^2+ 2ab + b^2= (a + b)^2$
$ 4 x^4+12 x^3+9 x^2 $
→$ 4 x^4+12 x^3+9 x^2 $