Question
Multiply the binomials: $(y - 8)$ and $(3y - 4)$

Answer

$(y - 8) \times (3y - 4) = y(3y - 4) - 8(3y - 4)$
$= y \times 3y - y \times 4 - 8 \times 3 y - 8 \times -4$
$= 3y^2- 4y - 24y + 32$
$= 3y^2- 28y + 32$

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