Multiply the following : (3 x^2+4 x-8 ), (2 x^2-4 x+3 )

Question

Multiply the following :
$\left(3 x^2+4 x-8\right),\left(2 x^2-4 x+3\right)$

✓

Answer

We have, $\left(3 x^2+4 x-8\right)$ and $\left(2 x^2-4 x+3\right)$
$\therefore\left(3 x^2+4 x-8\right)\left(2 x^2-4 x+3\right)$
$=3 x^2\left(2 x^2-4 x+3\right)+4 x\left(2 x^2-4 x+3\right) -8\left(2 x^2-4 x+3\right)$
$=6 x^4-12 x^3+9 x^2+8 x^3-16 x^2+12 x-16 x^2+32 x-24$
$=6 x^4-12 x^3+8 x^3+9 x^2-16 x^2 -16 x^2 +12 x+32 x-24\quad$ [grouping like terms]
$=6 x^4-4 x^3-23 x^2+44 x-24$

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