Question
Multiply:
$ \left(x^2+y^2\right) b y(3 a+2 b) $
$ \left(x^2+y^2\right) b y(3 a+2 b) $
✓
Answer
To multiply, we will use distributive law as follows:
$ \left(x^2+y^2\right) b y(3 a+2 b) $
$ =x^2(3 a+2 b)+y^2(3 a+2 b) $
$ =3 a x^2+2 b x^2+3 a y^2+2 b y^2 $
Thus, the answer is $3 a x^2+2 b x^2+3 a y^2+2 b y^2 $.
$ \left(x^2+y^2\right) b y(3 a+2 b) $
$ =x^2(3 a+2 b)+y^2(3 a+2 b) $
$ =3 a x^2+2 b x^2+3 a y^2+2 b y^2 $
Thus, the answer is $3 a x^2+2 b x^2+3 a y^2+2 b y^2 $.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Solve: $5x + \frac{7}{2}=\frac{2}{2}x -14$
→Evaluate: $\sqrt[3]{64}$
→Find the square root of the following by long division method: $20657025$
→Using prime factorization method, find the following numbers are perfect squares? $441$
→By what least number should the given number be multiplied to get a perfect square number$?$ In case, find the number whose square is the new number. $3380$
→Aman's income is $20\%$ less than that of Anil. How much percent is Anil's income more than Aman's income$?$
→Find using distributivity.
(i) $\left\{\frac{7}{5} \times\left(\frac{-3}{12}\right)\right\}+\left\{\frac{7}{5} \times \frac{5}{12}\right\}$
→(i) $\left\{\frac{7}{5} \times\left(\frac{-3}{12}\right)\right\}+\left\{\frac{7}{5} \times \frac{5}{12}\right\}$
Find the smallest whole number with which $2800$ should be divided so as to get a perfect square. Also find the square root of the square number so obtained.
→Verify the property $x \times y=y \times x$ of rational numbers using
(i) $x=\frac{-5}{7}$ and $y=\frac{14}{15}$ $\quad$ (ii) $x=\frac{2}{3}$ and $y=\frac{9}{4}$
→(i) $x=\frac{-5}{7}$ and $y=\frac{14}{15}$ $\quad$ (ii) $x=\frac{2}{3}$ and $y=\frac{9}{4}$
Examine the table. (Each figure is divided into triangles and the sum of the angles deduced from that.)
What can you say about the angle sum of a convex polygon with n number of sides?
→| Figure |  |
 |
 |
 |
| Side | $3$ | $4$ | $5$ | $6$ |
| Angle sum | $180^\circ$ | $2 \times 180^{\circ}$ $=(4-2) \times 180^{\circ}$ |
$3 \times 180^{\circ}$ $=(5-2) \times 180^{\circ}$ |
$4 \times 180^{\circ} $ $=(6-2) \times 180^{\circ}$ |