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N _ 2(g) + H _ 2(g) NH _ 3( g )

Vidyadip · Accepted Answer

Rewrite the given equation as it is N _ 2(g) + H _ 2(g) NH _ 3( g ) Step 2: Write the number of atoms of each element in the unbalanced equation on both sides of equations Element :[" Number of atoms in "],[" reactants "]: :[" Number of atoms in "],[" products "]: N 2 1 H 2 3 Step 3: In the given equation. NH _3 is a compound and it contains hydrogen element. On the left hand side there are two H atoms and on the right side 3 H atoms. Equalise H atoms on both sides. Hydrogen atoms In reactants In products Initially 2 3 To balance 3x2 2x3 To equalise the number of hydrogen atoms, we use 3 as the factor in the reactant and 2 as the factor in the products. Now the equation becomes N _2+3 H _2 2 NH _3 Now, count the atoms of each element on both sides of the equation. The number of atoms on both sides are equal. Hence, the balanced equation is N _2+3 H _2 2 NH _3 Now indicate the physical states of the reactants and products N _ 2(g) +3 H _ 2(g) 2 NH _ 3( g )

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Element	{:[" Number of atoms in "],[" reactants "]:}	{:[" Number of atoms in "],[" products "]:}
N	2	1
H	2	3

Hydrogen atoms	In reactants	In products
Initially	2	3
To balance	3x2	2x3

P-1 Chemical reactions and equations — Science STD 10 — Question

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