MCQ
${N_2}$ forms $NC{l_3}$, whereas $P$ can form both $PC{l_3}$ and $PC{l_5}$. Why
- ✓$P$ has low lying $3d$ orbitals, which can be used for bonding but ${N_2}$ does not have low lying $3d$ orbital
- B${N_2}$ atom is larger than $P$ in size
- C$P$ is more reactive towards $Cl$ than ${N_2}$
- DNone of these