Nd ^ 2+ = - Vidyadip

MCQ

$Nd ^{2+}=$

A
$4 f^2 6 s^2$
✓
$4 f^4$
C
$4 f^3$
D
$4 f ^4 6 s ^2$

✓

Answer

Correct option: B.

$4 f^4$

b
$Nd (60)=[ Xe ] 4 f ^4 5 d ^0 6 s ^2$

$Nd ^{2+}=[ Xe ] 4 f ^4 5 d ^0 5 s ^0$

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