MCQ
Newton-second is the unit of
- AVelocity
- BAngular momentum
- ✓Momentum
- DEnergy
So the unit of momentum will be equal to Newton-sec.
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$\frac{\text{i}_1+\text{i}_2}{\sqrt{2}}$
$\frac{|\text{i}_1+\text{i}_2|}{\sqrt{2}}$
$\sqrt{\frac{\text{i}_1^2+\text{i}_2^2}{2}}$
$\sqrt{\frac{\text{i}_1^2+\text{i}_2^2}{\sqrt{2}}}$
[Assume length of wires $A$ and $B$ are same]
