Question
$NH _3$ solution is added to $CuSO _4$ solution drop by drop and then in excess.

Answer

When NH 3 solution is added to CUSO4 solution drop by drop, ammonia ions completely react with copper sulphate and precipitates of copper hydroxide are formed. $CuSO _{4( aq )}+2 NH _{3( aq )}+2 H _2 O _{(0)} \rightarrow Cu ( OH )_{2(s)}+\left( NH _4\right)_2 SO _{4( aq )}$
But when we add excess of ammonia, the precipitate dissolves and a soluble complex is formed.
$CuSO_{4(a q)}+4 NH_{3(a q)} \rightarrow\left[Cu\left(NH_3\right)_4\right] SO_{4(a q)}$

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