N H_4 Cl is acidic, because - Vidyadip

MCQ

$N{H_4}Cl$ is acidic, because

✓
On hydrolysis $N{H_4}Cl$ gives weak base $N{H_4}OH$ and strong acid $HCl$
B
Nitrogen donates a pair of electron
C
It is a salt of weak acid and strong base
D
On hydrolysis $N{H_4}Cl$ gives strong base and weak acid

✓

Answer

Correct option: A.

On hydrolysis $N{H_4}Cl$ gives weak base $N{H_4}OH$ and strong acid $HCl$

(a) $N{H_3}Cl + {H_2}O$ $ \rightleftharpoons $ $N{H_4}OH + HCl$

$N{H_4}Cl$ is a salt of weak base & strong acid so solution will be acidic.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 6.2. Equilibrium - II (icon Equilibrium)→6.2. Equilibrium - II (icon Equilibrium) — all question types→Chemistry STD 11 Science question papers→Rajasthan Board STD 11 Science question papers→Rajasthan Board question paper generator→

Similar questions

The electronic configuration of chromium is

The unit of amount of substance is:

Calculate the amount of ${(N{H_4})_2}S{O_4}$ in grams which must be added to $500 $ $ml$ of $0.200\,M\,N{H_3}$ to yield a solution with $pH = 9.35$ $({K_b}$ for $N{H_3} = 1.78 \times {10^{ - 5}})$ ........$gm$

Equal volumes of $0.1\, M$ $AgNO_3$ and $0.2\, M$ $NaCl$ mixed. The concentration of $NO_3^-$ ion in the mixture will be ............ $\mathrm{M}$

Given are two statements one is labelled as Assertion $A$ and other is labelled as Reason $R$.

Assertion $A$ :Magnesium can reduce $Al _{2} O _{3}$ at a temperature below $1350^{\circ} C$, while above $1350^{\circ} C$ aluminium can reduce $MgO$.

Reason $R$ : The melting and boiling points of magnesium are lower than those of aluminium.

In light of the above statements. choose most appropriate answer from the options given below

Which reaction involves a change in the electron pair geometry for the underlined element ?

The following reaction take place in high yields.

Use your knowledge of alkene chemistry to predict a product even though you have never seen this reaction before

A completely filled $d$-orbital $({d^{10}})$

How much ....$kJ$ energy is released when $6$ mole of octane is burnt in air ? Given $\Delta H_f^o$ for $C{O_2}(g),\,{H_2}O(g)$ and ${C_8}{H_{18}}(l)$ respectively are $-490,-240\, and + 160 \,kJ/mol$

When treated with ammoniacal cuprous chloride, which one among the following forms copper derivative