3. trignometrical ratios,functions and identities — ગણિત ધોરણ 11 સાયન્સ — Question

$\sin 1( rad )=\sin 57.295( deg )$

$\sin 2(r a d)=\sin 114.591(\operatorname{deg})$

$\sin 3(r a d)=\sin 171.887(\operatorname{deg})$

These three angles are in 1 st and IInd quadrants

And $\sin \theta=\sin (180-\theta)$

On the curve $y=\sin x$ as we move towards $\pi / 2$ we get the same value.

$\sin (114.591)=\sin (65.409)$ and $\sin (171.887)=\sin (8.113)$

Hence $\sin 3<\sin 1<\sin 2$