- A$(C-O)$ bond length during complex formation increases than that of isolated $CO$
- B$CO$ will act as strong field ligand
- CComplex have tetrahedral geometry
- ✓All of the above correct
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[Given : $\mathrm{K}_{\mathrm{f}}=1.86 \,\mathrm{~K} \,\mathrm{~kg} \,\mathrm{~mol}^{-1} ;$ Density of water $=$ $1.00 \,\mathrm{~g}\, \mathrm{~cm}^{-3} ;$ Freezing point of water $\left.=273.15\, \mathrm{~K}\right]$

Which combination gives the highest yield of $z,$ at equilibrium.
$E ^0\left( Fe ^{3+} . Fe ^{2+}\right)=+0.77 V $
$E ^0\left( Fe ^{2+} . Fe \right)=-0.44 V $
$E ^{\circ}\left( Cu ^{2+} . Cu \right)=+0.34 V $
$E ^0\left( Cu ^{+} . Cu \right)=+0.52 V $
$E ^{\circ}\left( O _2( g )+4 H ^{+}+4 e ^{-} \rightarrow 2 H _2 O \right)=+1.23 V $
$E ^{\circ}\left( O _2( g )+2 H _2 O +4 e ^{-} \rightarrow 4 OH \right)=+0.40 V $
$E ^0\left( Cr ^{3+} . Cr \right)=-0.74 V $
$E ^{\circ}\left( Cr ^{2+} . Cr \right)=-0.91 V$
Match $E ^{\circ}$ of the rebox pair in List $I$ with the values given in List $II$ and select the correct answer using the code given below the lists:
| List $I$ | List $II$ |
| $P.$ $\quad E ^{\circ}\left( Fe ^{3+}, Fe \right)$ | $1.$ $\quad-0.18 V$ |
| $Q.$ $\quad E ^{\circ}\left(4 H _2 O \rightleftharpoons 4 H ^{+}+4 OH ^{-}\right)$ | $2.$ $\quad-0.4 V$ |
| $R.$ $\quad E ^{\circ}\left( Cu ^{2+}+ Cu \rightarrow 2 Cu ^{+}\right)$ | $3.$ $\quad-0.04 V$ |
| $S.$ $\quad E ^{\circ}\left( Cr ^{3+}, Cr ^{+2}\right)$ | $4.$ $\quad-0.83 V$ |
Codes: $ \quad P \quad Q \quad R \quad S $
$\begin{array}{*{20}{c}}{ - OAc}\\{\rm{I}}\end{array}$$\begin{array}{*{20}{c}}{ - OMe}\\{{\rm{II}}}\end{array}$$\begin{array}{*{20}{c}}{ - OS{O_2}Me}\\{{\rm{III}}}\end{array}$$\begin{array}{*{20}{c}}{ - OS{O_2}C{F_3}}\\{{\rm{IV}}}\end{array}$
The order of leaving group ability is
$\mathrm{Zn}(\mathrm{s})+\mathrm{Cu}^{2+}(0.02 \mathrm{M}) \rightarrow \mathrm{Zn}^{2+}(0.04 \mathrm{M})+\mathrm{Cu}(\mathrm{s})$
$\mathrm{E}_{\text {cell }}=...... \,\times 10^{-2} \,\mathrm{~V} { (Nearest integer) }$
${\left[\text { Use }: \mathrm{E}_{\mathrm{Cu} / \mathrm{Cu}^{2+}}^{0}=-0.34\, \mathrm{~V}, \mathrm{E}_{2 \mathrm{n} / \mathrm{Zn}^{2+}}^{0}=+0.76 \,\mathrm{~V}\right.}$
$\left.\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059\, \mathrm{~V}\right]$