Question
निम्नलिखित समीकरणों को हल कीजिए :
$\frac{3 p}{4}=6$
$\frac{3 p}{4}=6$
$3 p=24$
$\frac{3 p}{3}=\frac{24}{3}$
$p=8$
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$5+z+z x$
$\begin{aligned} & 10 p q, 7 p, 8 q,-p^2 q^2,-7 q p,-100 q,-23,12 q^2 p^2,-5 p^2, 41,2405 p, 78 q p \\ & 13 p^2 q, q p^2, 701 p^2\end{aligned}$
$45^{\circ}, 45^{\circ}$

$\frac{b}{2}=6$

$2.1$
$a^2+b^2$
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