Question
निम्नलिखित व्यंजकों के गुणनखंड कीजिए : $a^2+8 a+16$

Answer

$a^2+8 a+16=a^2+(4+4) a+4 \times 4$सर्वसमिका $x^2+(a+b) x+ab= (x+a) (x+b)$ के प्रयोग से,
यहाँ x = a, a = 4 and b = 4
$a^2+8 a+16=(a+4)(a+4)=(a+4)^2$

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