Nitric acid converts iodine into

$9\, mol$ $O_2$ and $14\, mol$ $N_2$ here allowed to react. When $3\, mol$ $O_2$ remains unreacted, till then how many moles of $N_2O_3$ would have been produced?

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A reaction takes place in three steps with individual rate constant and activation energy,

	Rate constant	Activation energy
Step $1$	$k_1$	$E_{a_1} = 180\,kJ /mol$
Step $2$	$k_2$	$E_{a_2} = 80\,kJ /mol$
Step $3$	$k_3$	$E_{a_3} = 50\,kJ /mol$

overall rate constant, $k = {\left( {\frac{{{k_1}{k_2}}}{{{k_3}}}} \right)^{2/3}}$ overall activation energy of the reaction will be ........ $kJ\,mol$

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An example of a compound with the functional group $' - O - '$ is

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Which of the following solutions can act as buffer

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Which of the following $C - H$ bond has the lowest bond dissociation energy

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Which is not correctly matched

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Which has the maximum atomic radius

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Consider the following complex ions $ \mathrm{P}=\left[\mathrm{FeF}_6\right]^{3-} $ , $ \mathrm{Q}=\left[\mathrm{V}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+} $ , $ \mathrm{R}=\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$ The correct order of the complex ions, according to their spin only magnetic moment values (in $B.M.$) is :