MCQ
Nitrogen is obtained when $NaN{O_2}$ reacts with
- ✓$N{H_4}Cl$
- B$N{H_4}N{O_3}$
- C${(N{H_4})_2}C{O_3}$
- D$N{H_4}OH$
$N{H_4}N{O_2} \longrightarrow {N_2} + 2{H_2}O$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$B.E. (H-H) = x_1 ; B.E. (O = O) = x_2$ ;
$B.E. (O -H) = x_3$
Heat of vaporisation of water $= x_4$ then $\Delta {H_f}$ [heat of formation of liquid water] is

$2 Cu ^{2+}+4 X ^{-} \rightarrow Cu _2 X _2( s )+ X _2$