MCQ
Nitrosobenzene can be prepared by oxidizing aniline from
- A${H_2}S{O_4}$
- ✓${H_2}S{O_5}$
- C${H_2}S{O_3}$
- D${K_2}C{r_2}{O_7}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| $List-I$ (Compound) | $List-II$ (Shape) |
| $(A)$ $BrF _{5}$ | $(I)$ bent |
| $(B)$ $\left[ CrF _{6}\right]^{3-}$ | $(II)$ square pyramidal |
| $(C)$ $O _{3}$ | $(III)$ trigonal bipyramidal |
| $(D)$ $PCl _{5}$ | $(IV)$ octahedral |
Choose the correct answer from the options given below.
Assertion $(A)$ $:$ When Cu $(II)$ and sulphide ions are mixed, they react together extremely quickly to give a solid.
Reason $(R)$ $:$ The equilibrium constant of $Cu ^{2+}( aq )+ S ^{2-}( aq ) \rightleftharpoons \operatorname{CuS}( s )$ is high because the solubility product is low.

$I$ . $Zn +$ conc. $HNO_3$ (hot) $\to Zn(NO_3)_2 + X + H_2O$
$II$. $Zn +$ dil. $HNO_3$ (cold) $\to Zn(NO_3)_2 + Y + H_2O$
Compounds $X$ and $Y$ are respectively
If $(n=4)$ then di-carboxylic acid. would be known as
| Column $I$ | Column $II$ | ||
| $(A)$ | Kohlrausch law can calculate | $(P)$ | $\frac{{\Lambda _m^c}}{{\Lambda _m^o}}$ |
| $(B)$ | Molar conductance ${\Lambda _m}$ | $(Q)$ | $\frac{1}{R} \times \frac{l}{A}$ |
| $(C)$ | Specific conductance Kappa $\to (k)$ | $(R)$ | $\Lambda _m^o\,of\,c{a_3}{(P{O_4})_2}$ |
| $(D)$ | Degree of ionization of weak electrolyte | $(S)$ | $\frac{{k \times 1000}}{M}$ |
Which of the following option show correct matches