MCQ
Normal butane convert into isobutane by
- A$LiAl{H_4}$
- ✓$AlC{l_3}$
- C$NaB{H_4}$
- D$Zn / HCl$
✓
Answer
Correct option: B.
$AlC{l_3}$
b
(b) $\mathop {C{H_3}C{H_2}C{H_2}C{H_3}}\limits_{n - {\rm{butane}}} \xrightarrow[\Delta]{Anhyd AlCl_3} \mathop {C{H_3} - \mathop {CH}\limits_{\mathop {|\,\,\,\,\,}\limits_{\,\,C{H_3}} } - C{H_3}}\limits_{{\rm{iso}}\,{\rm{butane}}} $
(b) $\mathop {C{H_3}C{H_2}C{H_2}C{H_3}}\limits_{n - {\rm{butane}}} \xrightarrow[\Delta]{Anhyd AlCl_3} \mathop {C{H_3} - \mathop {CH}\limits_{\mathop {|\,\,\,\,\,}\limits_{\,\,C{H_3}} } - C{H_3}}\limits_{{\rm{iso}}\,{\rm{butane}}} $
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