$N =\frac{\text { Gram eq.of Solute }}{\text { Volume of sol.in litre }}$
$=\frac{\text { Weight }}{\text { Equivalent weight }} \times \frac{1000}{V \,m l}$
Equivalent Weight $=\frac{\text { Molar Mass }}{n}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$M(s) + \frac{1}{2}{O_2}(s)\, \to \,MO(s)\,$ and $C(s) + \frac{1}{2}{O_2}(g)\, \to \,CO(s)\,$
Identify the correct statement
$(I)$ $BO_3^{-3} > CO_3^{-2} > NO_3^-$
$(II)$ $ClO_4^-> SO_4^{-2} > PO_4^{-3}$
$(III)$ $BF_3 > BCl_3 > BBr_3$
$(IV)$ $AlCl_3 > BCl_3$
$C(s) + {O_2}(g) \to C{O_2}(g),\Delta H = - 394\,kJ$
$2{H_2}(g) + {O_2}(g) \to 2{H_2}O(l),\,\Delta H = 568\,kJ$
$C{H_4}(g) + 2{O_2}(g)\,\, \to \,\,C{O_2}(g) + 2{H_2}O(l)$ $\Delta H = - 892\,kJ$ Heat of formation of $C{H_4}$ is.....$kJ$