Normality (N) of a solution is equal to

MCQ

Normality $(N)$ of a solution is equal to

A
$\frac{{{\rm{No}}{\rm{. \,of\, moles\, of\, solute}}}}{{{\rm{Volume\, of \,solution\, in \,litre}}}}$
✓
$\frac{{{\rm{No}}{\rm{. \,of\, gram\, equivalent\, of\, solute}}}}{{{\rm{Volume \,of\, solution\, in \,litre }}}}$
C
$\frac{{{\rm{No}}\,{\rm{. \,of\, moles \,of \,solute}}}}{{{\rm{Mass \,of\, solvent\, in\, kg}}}}$
D
None of these

✓

Answer

Correct option: B.

$\frac{{{\rm{No}}{\rm{. \,of\, gram\, equivalent\, of\, solute}}}}{{{\rm{Volume \,of\, solution\, in \,litre }}}}$

b
The normality of a solution is the gram equivalent weight of a solute per liter of solution. It may also be called the equivalent concentration. It is indicated using the symbol $N$.

$N =\frac{\text { Gram eq.of Solute }}{\text { Volume of sol.in litre }}$

$=\frac{\text { Weight }}{\text { Equivalent weight }} \times \frac{1000}{V \,m l}$

Equivalent Weight $=\frac{\text { Molar Mass }}{n}$

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