MCQ
${n^{th}}$ term of the series $3.8 + 6.11 + $ $9.14 + 12.17 + .....$ will be
- ✓$3n(3n + 5)$
- B$3n(n + 5)$
- C$n(3n + 5)$
- D$n(n + 5)$
First factors are $3, 6, 9, 12$ whose ${n^{th}}$ term is $3n$
and second factors are $8, 11, 14, 17$
${t_n} = [8 + (n - 1)3] = (3n + 5)$
Hence ${n^{th}}$ term of given series $ = 3n(3n + 5)$.
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