MCQ
Number of angular nodes for $4d$ orbital is $ ...........$
- A$4.$
- B$3$
- ✓$2.$
- D$1.$
✓
Answer
Correct option: C.
$2.$
Number of radial nodes in any orbital $= (n - l - 1)$
$= (4 - 2 - 1) = 1$
Total number of nodes $= ( n - 1 )$
$= (4 - 1) = 3$
So angular node $=$ total node $-$ radial node
$= (3 - 1) = 2.$
$= (4 - 2 - 1) = 1$
Total number of nodes $= ( n - 1 )$
$= (4 - 1) = 3$
So angular node $=$ total node $-$ radial node
$= (3 - 1) = 2.$
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