MCQ
Number of $\pi $ electrons present in naphthalene is
- A$4$
- B$6$
- ✓$10$
- D$14$
$\pi $ bonds $=5$
hence electrons are double
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${N_{2(g)}} + 3{H_{2(g)}} \rightleftharpoons \,2N{H_{3(g)}}$ at equilibrium at constant volume will lead to
$(iii)$ Size $(iv)$ Energy level
(Molar Mass : Bromine $=80\; g / mol$ )
(IMAGE)
$[A]$ ( $M$ and $O)$ and ( $N$ and $P$ ) are two pairs of diastereomers
$[B]$ Bromination proceeds through trans-addition in both the reactions
$[C]$ $O$ and $P$ are identical molecules
$[D]$ (M and $O)$ and ( $N$ and $P)$ are two pairs of enantiomers