MCQ
Number of waves formed by a Bohr electron in one complete revolution in its third orbit is
- A$0$
- B$1$
- C$2$
- ✓$3$
✓
Answer
Correct option: D.
$3$
d
Angular momentum of $n^{t h}$ bohr orbit $=\frac{n h}{2 \lambda}$
Angular momentum of $n^{t h}$ bohr orbit $=\frac{n h}{2 \lambda}$
$m \cdot v \cdot r_{n}=\frac{n h}{2 \lambda}$
$m v=\frac{h}{\lambda}$ (according to de Broglie)
$\left(\frac{h}{\lambda}\right) r_{n}=\frac{n h}{2 \lambda}$
$n \lambda=2 \pi r_{n}(n=3)$
$2 \lambda=2 \pi r_{n}$
these the circumference of $3^{r d}$ Bohr orbit equal to 3 terms the wavelength of an electron makes this revolution around the $3^{r d}$ orbit
Hence no. of the wave $=3$
Hence, the correct option is $\mathrm{D}$
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