Question
o-nitrophenol is more acidic than $o-$methoxyphenol.
✓
Answer
$-R$ and $-I$ effect of $-NO_2$ group decreases the electron density in $O-H$ bond and make loss of proton easy in $O-$nitrophenol whereas $+R$ effect of $-\ce{OCH_3}$ group increases the electron density in $O-H$ bond and makes release of proton difficult in $o-$methoxyphenol.
That is, why $o-$nitrophenol is stronger acid than $o-$methoxyphenol.
That is, why $o-$nitrophenol is stronger acid than $o-$methoxyphenol.
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→Match the starting materials given in Column $I$ with the products formed by these $($Column $II)$ in the reaction with $II.$
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Column $I$
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Column $II$
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| $(i)$ | $CH_3-o-CH_3$ | $(a)$ |
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| $(ii)$ |
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$(b)$ |
$\ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3 \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \\ \text{CH}_3-\text{C}-\text{I}+\text{CH}_3\text{OH} \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$
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| $(iii)$ |
$\ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3 \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \\ \text{H}_3\text{C}-\text{C}-\text{O}-\text{CH}_3 \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$
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$(c)$ |
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| $(iv)$ |
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$(d)$ | $CH_3-OH + CH_3-I$ |
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$(e)$ |
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$(f)$ |
 |
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$(g)$ |
$\ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3 \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \\ \text{CH}_3-\text{C}-\text{OH}+\text{CH}_3\text{I} \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$
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