On a smooth inclined plane, a body of mass $M$ is attached between two springs. The other ends of the springs are fixed to firm supports. If each spring has force constant $K$, the period of oscillation of the body (assuming the springs as massless) is
Medium
Download our app for free and get started
(a) Slope is irrelevant hence $T = 2\pi {\left( {\frac{M}{{2K}}} \right)^{1/2}}$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1Aheavy brass sphere is hung from a light spring and is set in vertical small oscillation with a period $T.$ The sphere is now immersed in a non-viscous liquid with a density $1/10\,th$ the density of the sphere. If the system is now set in vertical $S.H.M.,$ its period will beView Solution
- 2Two masses $m_1=1 \,kg$ and $m_2=0.5 \,kg$ are suspended together by a massless spring of spring constant $12.5 \,Nm ^{-1}$. When masses are in equilibrium $m_1$ is removed without disturbing the system. New amplitude of oscillation will be .......... $cm$View Solution
- 3The displacement of simple harmonic oscillator after $3$ seconds starting from its mean position is equal to half of its amplitude. The time period of harmonic motion is $\dots \; s$View Solution
- 4A simple pendulum, suspended from the ceiling of a stationary van, has time period $T$. If the van starts moving with a uniform velocity the period of the pendulum will beView Solution
- 5View SolutionThe total spring constant of the system as shown in the figure will be
- 6A simple pendulum is attached to the roof of a lift. If time period of oscillation, when the lift is stationary is $T$. Then frequency of oscillation, when the lift falls freely, will beView Solution
- 7The length of the second pendulum on the surface of earth is $1\, m$. The length of seconds pendulum on the surface of moon, where g is 1/6th value of $g$ on the surface of earth, isView Solution
- 8A particle is vibrating in a simple harmonic motion with an amplitude of $4\, cm.$ At what displacement from the equilibrium position, is its energy half potential and half kineticView Solution
- 9A spring mass system preforms $S.H.M.$ If the mass is doubled keeping amplitude same, then the total energy of $S.H.M.$ will become :View Solution
- 10The displacement of a particle varies according to the relation $x = 4(cos\pi t + sin\pi t).$ The amplitude of the particle isView Solution