On all the six surfaces of a unit cube, equal tensile force of $F$ is applied. The increase in length of each side will be ($Y =$ Young's modulus, $\sigma $= Poission's ratio)
A$\frac{F}{{Y(1 - \sigma )}}$
B$\frac{F}{{Y(1 + \sigma )}}$
C$\frac{{F(1 - 2\sigma )}}{Y}$
D$\frac{F}{{Y(1 + 2\sigma )}}$
Medium
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C$\frac{{F(1 - 2\sigma )}}{Y}$
c (c) Tensile strain on each face$ = \frac{F}{Y}$
Lateral strain due to the other two forces acting on perpendicular faces$ = \frac{{ - 2\sigma F}}{Y}$
Total increase in length $ = (1 - 2\sigma )\frac{F}{Y}$
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