MCQ
On charging the lead accumulator cell :
- A$PbO _2$ dissolves
- B$PbSO _4$ deposits on the lead electrode
- ✓$H _2 SO _4$ is formed again
- DThe amount of $H _2 SO _4$ is less
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$(A)$ $\left[ FeF _{6}\right]^{3-}$
$(B)$ $\left[ Fe ( CN )_{6}\right]^{3-}$
$(C)$ $\left[ MnCl _{6}\right]^{3-}$ (high spin)
$(D)$ $\left[ Mn ( CN )_{6}\right]^{3-}$
$A, \,C$ and $D$ are