MCQ
On dividing $p(4p^2- 16)$ by $4p(p - 2)$, we get
- A$2p + 4$
- B$2p - 4$
- ✓$p + 2$
- D$p - 2$
✓
Answer
Correct option: C.
$p + 2$
We have,
$\frac{\text{p}(4\text{p}^2-16)}{4\text{p}(\text{p}-2)}=\frac{\text{p}\big[(2\text{p})^2-4^2\big]}{4\text{p}(\text{p}-2)}$
$=\frac{(2\text{p}-4)(2\text{p}+4)}{4(\text{p}-2)}$
$=\frac{2(\text{p}-2).2(\text{p}+2)}{4(\text{p}-2)}$
$=\frac{4(\text{p}-2)(\text{p}+2)}{4(\text{p}-2)}$
$=\text{p}+2$
$\frac{\text{p}(4\text{p}^2-16)}{4\text{p}(\text{p}-2)}=\frac{\text{p}\big[(2\text{p})^2-4^2\big]}{4\text{p}(\text{p}-2)}$
$=\frac{(2\text{p}-4)(2\text{p}+4)}{4(\text{p}-2)}$
$=\frac{2(\text{p}-2).2(\text{p}+2)}{4(\text{p}-2)}$
$=\frac{4(\text{p}-2)(\text{p}+2)}{4(\text{p}-2)}$
$=\text{p}+2$
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