MCQ
On factorising $14 \mathrm{pq}+35$ pqr, we get:
  • A
    $\mathrm{pq}(14+35 r)$
  • B
    $\mathrm{p}(14 \mathrm{q}+35 \mathrm{qr})$
  • C
    $\mathrm{q}(14 \mathrm{p}+35 \mathrm{pr})$
  • $7 \mathrm{pq}(2+5 \mathrm{r})$

Answer

Correct option: D.
$7 \mathrm{pq}(2+5 \mathrm{r})$
$14pq + 35pqr$
$=2.7 . p . q+5.7 . p . q . r$
$=7 \mathrm{pq}(2+5 r)$

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