MCQ
On heating ammonium dichromate and barium azide separately we get
  • $\mathrm{N}_2$ in both cases.
  • B
    $\mathrm{N}_2$ with ammonium dichromate and $NO$ with barium azide.
  • C
    $\mathrm{N}_2 \mathrm{O}$ with ammonium dichromate and $\mathrm{N}_2$ with barium azide.
  • D
    $\mathrm{N}_2 \mathrm{O}$ with ammonium dichromate and $\mathrm{NO}_2$ with barium azide.

Answer

Correct option: A.
$\mathrm{N}_2$ in both cases.
$(\text{NH}_4)_2\text{Cr}_2\text{O}_7\xrightarrow{\ \ \ \ \ \ \ \ \ }\text{N}_2+\text{Cr}_2\text{O}_3+4\text{H}_2\text{O}$
$\text{Ba}(\text{N}_3)_2\xrightarrow{\ \ \ \ \ \ \ \ \ }3\text{N}_2+\text{Ba}$

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