MCQ
On heating $NaCl$ + ${K_2}C{r_2}{O_7}$ + $conc.{H_2}S{O_4}$, the gas comes out is
- A${O_2}$
- B$C{l_2}$
- C$CrOC{l_2}$
- ✓$Cr{O_2}C{l_2}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\,\,\begin{array}{*{20}{c}}
{C{H_3} - C - H\,} \\
\,\,\,\,{||} \\
\,\,\,\,{O\,}
\end{array} + \,C{H_3} - C{H_2} - CHO\xrightarrow{{\overline O H/{H_2}O}}$