MCQ
On heating $NaNO_3$ gives
  • $O_2$
  • B
    $NO_2$
  • C
    $O_2 + NO_2$
  • D
    $Na_2O$

Answer

Correct option: A.
$O_2$
a
$NaN{O_3}\xrightarrow{\Delta }NaN{O_2} + \frac{1}{2}{O_2}$

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