MCQ
On passing a current through $KCl$ solution, $19.5\,g$ of potassium is deposited. If the same quantity of electricity is passed through a solution of aluminium chloride, the amount of aluminium deposited is ............ $\mathrm{g}$
  • $4.5$
  • B
    $9$
  • C
    $13.5$
  • D
    $27$

Answer

Correct option: A.
$4.5$
a
$K^++ e^-= K$

$Al^{3+} +3 e^- = Al$

Aluminium requires 3 times the amount of electricity to deposit one mole

Moles of $K$ deposited $=19.5 / 39=0.5$

Moles of $Al$ deposited $=0.5 / 3=1 / 6$

Mass of $Al$ deposited $=27 \times 1 / 6$

$=4.5 g$

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