MCQ
On the intervl $ (1,3)$, the function $f(x) = 3x + {2 \over x}$ is
- AStrictly decreasing
- ✓Strictly increasing
- CDecreasing in $ (2, 3) $ only
- DNeither increasing nor decreasing
==> $f'(x) = 3 - \frac{2}{{{x^2}}}$
Clearly $f'(x) > 0$ on the interval $(1, 3)$
$f(x)$ is strictly increasing.
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