- A$3.2$
- B$5.6$
- ✓$7.2$
- D$13.2$
$\therefore $ ${E_1} = \frac{{36E}}{5} = 7.2\,E$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\begin{array}{*{20}{c}}
{O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\
{||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,} \\
{C{H_3} - C - CH - CH - CH - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,CHO\,\,}
\end{array}$
is :

| $List-I$ | $List-II$ |
| $(A)$ $Cd ( s )+2 Ni ( OH )_{3}( s ) \rightarrow CdO ( s )+2 Ni ( OH )_{2}( s )+ H _{2} O (l)$ | $(I)$ Primary battery |
| $(B)$ $Zn ( Hg )+ HgO ( s ) \rightarrow ZnO ( s )+ Hg (l)$ | $(II)$ Discharging of secondary battery |
| $(C)$ $2 PbSO _{4}( s )+2 H _{2} O (l) \rightarrow Pb ( s )+ PbO _{2}( s )+ 2 H _{2} SO _{4}( aq )$ | $(III)$ Fuel cell |
| $(D)$ $2 H _{2}( g )+ O _{2}( g ) \quad \rightarrow 2 H _{2} O (l)$ | $(IV)$ Charging of secondary battery |
Choose the correct answer from the options given below.
$2AB_{2(g)} \rightleftharpoons 2AB_{(g)} + B_{2(g)}$
The degree of dissociation is $x$ and is small compared to $1.$ The expression relating the degree of dissociation $(x)$ with equilibrium constant $K_P$ and total pressure $P$ is