MCQ
One mole of any substance contains $6.022 \times 10^{23}$ atoms/ molecules. Number of molecules of $\ce{{H}_2{SO}_4}$ present in $100\ mL$ of $\ce{0.02M  {H}_2{SO}_4}$ solution is $ ..........$
  • $12.044 \times 10^{20}$ molecules.
  • B
    $6.022 \times 10^{23}$ molecules.
  • C
    $1 \times 10^{23}$ molecules.
  • D
    $12.044 \times 10^{23}$ molecules.

Answer

Correct option: A.
$12.044 \times 10^{20}$ molecules.
We knew thet $\text{M}=\frac{\text{n}}{\text{v}}$ or $\text{n}=\text{M}\times\text{V}\ (\text{in L})$
$\text{n}=0.02\times0.1=0.002$
No. of molecules $=\text{n}\times6.022\times10^{23}$
$=0.002\times6.022\times10^{23}=12.044\times10^{20}\ \text{molecules}$

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