One of the two identical conducing wires of length $L$ is bent in the form of a circular loop and the other one into a circular coil of $N$ identical turns. If the same current is passed in both, the ratio of the magnetic field at the central of the loop $(B_L)$ to that at the centre of the coil $(B_C),$; $.\,\frac {B_L}{B_C}$ will be
JEE MAIN 2019, Medium
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$B_{L}=\frac{\mu_{0} i}{2 R}$
$B_{C}=\frac{\mu_{0} N i}{2(R / N)}$
$\therefore \quad \frac{B_{L}}{B_{C}}=\frac{1}{N^{2}}$
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