10. Biomolecules — Chemistry STD 12 Science — Question

$K = \left( {4.5 \times {{10}^{11}}{S^{ - 1}}} \right){e^{ - \left( {28000\frac{{{K^2}mol}}{J}} \right)\frac{R}{T}}}$

The activation energy of reaction (in $J/mol$) is 

$(i)$ $Xe{O_3}$ $(ii)$ $XeO{F_4}$ $(iii)$ $Xe{F_6}$

Those having same number of lone pairs on Xe are