MCQ
Order of decreasing basic strengths of halides is
- A$F^- > Cl^- > I^- > Br^-$
- ✓$F^- > Cl^- > Br^- > I^-$
- C$I^- > Br^- > Cl^- > F^-$
- D$I^- > Cl^- > Br^- > F^-$
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(Given Atomic No. of $\mathrm{Ho}=67$ )
$\frac{2}{3} Al_2O_3 \rightarrow \frac{4}{3} Al + O_2,\,$ $\Delta G = +966\,kJ\,mol$
The potential difference needed for electrolytic reduction of $Al_2O_3$ at $500^o C$ is at least ...... $V$.