Question
Out of $C$ and $CO$, which is a better reducing agent for $ZnO?$

Answer

The two reduction reactions are:
$ZnO(s) + C(s) → Zn(s) + CO(g) ...(i)$
$ZnO(s) + CO(g) → Zn(s) + CO_2(g) ....(ii)$

In the first case, there is increase in the magnitude of $\Delta\text{S}^{\circ}$ while in the second case, it almost remains the same. In other words, $\Delta\text{G}^{\circ}$will have more negative value in the first case when $C(s)$ is used as the reducing agent than in the second case when $CO(g)$ acts as the reducing agent. Therefore, $C(s)$ is a better reducing agent.

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