MCQ
Out of $CHCl_3, CH_4$ and $SF_4$ the molecules do not having regular geometry are
- A$CHCl_3$ only
- ✓$CHCl_3$ and $SF_4$
- C$CH_4$ only
- D$CH_4$ and $SF_4$
$SF _4$ has lone pair on $S$ so it will increase bond angle due to repulsion hence $CHCl _3$ and $SF _4$ has not regular geometry.
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$(I)$ $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{Br}_{2}$
$(II)$ $ \mathrm{Na}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]$
$(III)$ $\mathrm{Na}_{3}\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]\left(\Delta_{0}>\mathrm{P}\right)$
$(IV)$ $\left(\mathrm{Et}_{4} \mathrm{N}\right)_{2}\left[\mathrm{CoCl}_{4}\right]$
$2NH_3 + 5F_2\,\,\to \,\, N_2F_4 + 6HF$